Question

Someoneee pleaseee helppp!!!

Answer 1

Answer:

$part\ a\ A'(1,2),\ B'(2,5),\ C'(5,2)$

$part\ b\ A"(-2,1),\ B"(-5,2),\ C"(-2,5)$

Step-by-step explanation:

Given co-ordinates are $A(-5,2),\ B(-4,5),\ C(-1,2).$

Part a

We will find the co-ordinate of ABC by translating 6 units to the right.

If any co-ordinate say $P(x,y)$ is translated $k$ units to the right then co-ordinate of translated point $P'$ will be $P'(x+k,y)$

Here we are translating 6 units to the right. So, our $k$ is 6.

Now, co-ordinates after translating is

$A(-5,2)\ =\ A(-5+6,2)\ =\ A'(1,2)\\B(-4,5)\ =\ B(-4+6,5)\ =\ B'(2,5)\\C(-1,2)\ =\ C(-1+6,2)\ =\ C'(5,2)$

Part b

Now, we will find the co-ordinate of ABC after translating 6 units to the right with a rotation of 90°.

When any point say $R'(x,y)$ is rotated 90° the new co-ordinate after rotation about the origin is $R''(-y,x)$.

So, new co-ordinates are

$A'(1,2)=A''(-2,1)\\\ B'(2,5)=B"(-5,2)\\\ C'(5,2)=C"(-2,5)$