Need help doing this and it'd be helpful if you explained how you did it!

Answer:
sinc=3/5
ab/bc=3/5
ac2= bc2 -ab2 ( use Pythagoras)
ac2=25-9
ac=4
tanc=ab/ac
=3/4 answer
Answer:
cos A = 4/5
tan A = 4/3
Step-by-step explanation:
We are told that the sine of Angle A is 3/5.
The sine is defined as the ratio (opposite side) / (hypotenuse).
Here we can assign the value 3 to the length to the opposite side and the value 5 to the hypotenuse. Since this triangle is a right triangle, the Pythagorean Theorem applies:
(opposite side)^2 + (adjacent side)^2 = (hypotenuse)^2.
To write the cosine of Angle A, which is defined as (adjacent side) / (hypotenuse), we need to find the length of the adjacent side:
| adjacent side | = √[ (hypotenuse)^2 - (opposite side)^2.
In this particular case,
| adjacent side | = +√[ 5^2 - 3^2 ], ior just 4.
Then: cos A = 4/5
To write tan A: Find the numerical ratio (opp side) / (adj side), which here is tan A = 3/4