Respuesta :

Answer:

d = -9

Step-by-step explanation:

First lets input our x value for g(x)

This gives us the integral

[tex]g(6) = \int\limits^6_{-4} {f(x)} \, dx[/tex]

First, we need to split this integral into the different aspects of the piecewise function. This will give us

[tex]g(6)=\int\limits^0_{-4} {4} \, dx +\int\limits^5_0 {-5} \, dx +\int\limits^6_5 {0} \, dx[/tex]

Now, we need to evaluate each of these integrals

[tex]\int\limits^0_{-4} {4} \, dx=4x|\limits^0_{-4}\\\\4(0)-4(-4)=16[/tex]

[tex]\int\limits^5_0 {-5} \, dx=-5x|\limits^5_0\\\\-5(5)--5(0)\\\\-25[/tex]

[tex]\int\limits^6_5 {0} \, dx=0[/tex]

Now all we need to do is add the values of each of these integrals

[tex]16-25=-9[/tex]

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