Question

Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00 degrees°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to Upper P82​, the 82nd percentile. This is the temperature reading separating the bottom 82% from the top 18 %.

Answer 1

Answer:

0.915

Step-by-step explanation:

Given that the readings of  the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00 degrees°C.

Let X represent the reading of the thermometer

X is N(0.1)

Or X is a standard normal variate

we have to find 82nd percentile

i.e. we find z such that

$P(Z\leq z) = 0.82\\z=0.915$

Sketch is attached

82nd percentile is 0.915