Answer:
Final speed of both the cars, V = 3.28 km/h
Explanation:
It is given that,
Mass of the railway car, [tex]m_1=5.8\times 10^5\ kg[/tex]
Initial speed of the railway car, [tex]u_1=9.1\ km/h=2.52\ m/s[/tex]
Mass of another car, [tex]m_2=8.7\times 10^5\ kg[/tex]
Initial speed of another car, [tex]u_2=0[/tex]
To find,
The speed of the coupled cars after the collision.
Solution,
It is a case of inelastic collision in which the linear momentum before and after the collision remains same. Let V is the coupled velocity of both of the cars. So,
[tex]m_1u_1+m_2u_2=(m_1+m_2)V[/tex]
[tex]V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}[/tex]
[tex]V=\dfrac{m_1u_1}{(m_1+m_2)}[/tex]
[tex]V=\dfrac{5.8\times 10^5\times 2.52778}{(5.8\times 10^5+8.7\times 10^5)}[/tex]
V = 1.011 m/s
or
V = 3.28 km/h
So, the speed of the coupled cars after the collision is 3.28 km/h. Hence, this is the required solution.