Question

An electron travels with speed 6.0×10^6 m/s between the two parallel charged plates shown in the figure. The plates are separated by 1.0 cm and are charged by a 200 Volt battery.

What magnetic field strength will allow the electron to pass between the plates without being deflected?

Answer 1

Answer:

B= 3.33 m T

Explanation:

Given that

Speed ,C= 6 x 10⁶  m/s

d= 1 cm = 0.01 m

V= 200 V

The electric field E given as

V= E .d

E=Electric field

d=Distance

V=Voltage

200 = 0.01 x E

E=20000 V/m

The relationship between magnetic and electric field given as

E= C x B

20000 = 6 x 10⁶   x B

B =3333.333 x 10⁻⁶ T

B= 3.33 x 10⁻³ T

B= 3.33 m T

Therefore the magnetic filed will be 3.33 m T.

Answer 2

The magnetic field is mathematically given as

B=3.33 mT

What magnetic field strength will allow the electron to pass between the plates without being deflected?

Question Parameters:

An electron travels with speed of 6.0×10^6 m/s

the plates are separated by 1.0 cm and are charged by a 200 Volt battery.

Generally, the equation for the  electric field E  is mathematically given as

V= E .d

Therefore

200 = 0.01 x E

E=20000 V/m

Where

E= C x B

20000 = 6 x 10⁶   x B

B= 3.33 m T

In conclusion, the magnetic field is

B=3.33 mT

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