Answer:
c. −1.22 × 10^4 K
Explanation:
Generally, the slope of an Arrhenius plot can be determined either from the graph of In k against 1/T or the available experimental data of the rate constant (k) and the absolute temperature. Mathematically,
[tex]slope = \frac{ln k_{2} -ln k_{1} }{\frac{1}{T_{2} }-\frac{1}{T_{1} } }[/tex]
Where:
[tex]k_{1} = 6.6*10^-4[/tex] L/(mol.s)
[tex]k_{2} = 2.9*10^-1[/tex] L/(mol.s)
[tex]T_{1} = 400[/tex] K
[tex]T_{2} = 500[/tex] K
slope = (ln 2.9*10^-1 - ln 6.6*10^-4)/(1/500 - 1/400)
slope = (-1.238+7.323)/(0.002-0.0025)
slope = 6.085/-0.0005 = -1.22*10^4 K