Answer:
Temperature of fussion, for the solution is -0.41°C
Explanation:
To solve this we need to apply the colligative property, freezing point the pression.
ΔT = Kf . m . i
ΔT = T° f pure solvent - T° f solution
Kf= cryoscopic constant (1.86° C / m for water)
m = molality (mol of solute/ 1kg of solvent)
i = Van't Hoff factor (number of ions dissolved in solution)
CaCl₂ → Ca²⁺ + 2Cl⁻ (for this salt, i = 3)
Molar mass calcium chloride = 110.98 g/m
8.27 g/ 110.98 g/m = 0.0745 m
0°C - T°f solution = 0.0745 m . 1.86°C /m . 3
0°C - T°f solution = 0.41°C
T°f solution = - 0.41°C
