Answer
given,
frequency = 600 Hz
speed of sound = 343 m/s
wavelength =
[tex]\lambda = \dfrac{v}{f}[/tex]
[tex]\lambda = \dfrac{343}{600}[/tex]
λ = 0.572 m
for destructive interference
path difference = [tex]\dfrac{\lambda}{2}[/tex]
path difference = [tex]\dfrac{0.572}{2}[/tex]
path difference = 0.286 m
b)
path difference will be equal to 0.286 m
the sound distance from the λ/2 from the first speaker will be out of phase with the sound at that first speaker.
Since the second speaker is described as being out of phase with the first, placing them λ/2 apart will make their sound constructively interfere.