Hi boys can you help me pls!!!!!!!

Rowan tosses a ball toward his opponent during a game of table tennis. Function h demonstrates the height of the ball, in meters, when it is a distance x meters away from Rowan.


h(x)=-1/4x^2+1/2x+1/2


Select the statement that accurately describes the maximum point of the graph modeling the height of the ball.


A.

The maximum height of the ball is 0.75 of a meter, which occurs when it is approximately 1 meter away from Rowan.

B.

The maximum height of the ball is 1 meter, which occurs when it is approximately 2.73 meters away from Rowan.

C.

The maximum height of the ball is 1 meter, which occurs when it is approximately 0.75 of a meter away from Rowan.

D.

The maximum height of the ball is 2.73 meters, which occurs when it is approximately 1 meter away from Rowan.

Respuesta :

Answer: OPTION A.

Step-by-step explanation:

Given the following function:

[tex]h(x)=-\frac{1}{4}x^2+\frac{1}{2}x+\frac{1}{2}[/tex]

You know that it represents the the height of the ball (in meters) when it is a distance "x" meters away from Rowan.

Since it is a Quadratic function its graph is parabola.

So, the maximum point of the graph modeling the height of the ball is the Vertex of the parabola.

You can find the x-coordinate of the Vertex with this formula:

[tex]x=\frac{-b}{2a}[/tex]

In this case:

[tex]a=-\frac{1}{4}\\\\b=\frac{1}{2}[/tex]

Then, substituting values, you get:

[tex]x=\frac{-\frac{1}{2}}{(2)(-\frac{1}{4}))}\\\\x=1[/tex]

Finally, substitute the value of "x" into the function in order to get the y-coordinate of the Vertex:

[tex]h(1)=y=-\frac{1}{4}(1)^2+\frac{1}{2}(1)+\frac{1}{2}\\\\y=0.75[/tex]

Therefore, you can conclude that:

The maximum height of the ball is 0.75 of a meter, which occurs when it is approximately 1 meter away from Rowan.

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