Question

How many covalent bonds will be drawn to phosphorous in PO43– for the dot structure that expands the octet to minimize formal charge and if necessary places negative formal charges on the most electronegative atom(s).

Answer 1

Answer:

5 (five)

Explanation:

In $PO^{3-} _{4}$, the number of valence electrons of phosphorus is five while that of each of the oxygen atom is six. The oxygen atoms form three single bonds and a single double bond with the phosphorus. Therefore, the number of covelent bonds around the compound in order to ensure that the dot structure can expand the octet to reduce the formal charge is 5 (five).

Answer 2

There are total 5 covalent bonds will be drawn to phosphorous in $PO_4^{3-}$.

Structure of $PO_4^{3-}$:

In $PO_4^{3-}$, the quantity of valence electrons of phosphorus is five while that of every one of the oxygen particle is six. The oxygen particles structure three single bonds and a solitary two fold bond with the phosphorus. Consequently, the quantity of covalent bonds around the compound to guarantee that the speck construction can grow the octet to lessen the formal charge is 5 (five).

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