We have to find two equations because we are working with two variables.
Equation 1: 80x+100y=560 (we know this because speed times time equals distance)
Equation 2: x+y=560/93 (we know this because total distance over total time is average speed)
Let us solve the system of equations by substitution.
x+y=560/93 ---> x=560/93-y
80x+100y=560
80(560/93-y)+100y=560
y=3.91 hours approx.
Now we can plug in x to solve for y.
x+3.91=560/93
x=2.11 hours approx.
answer: x=2.11 hours approx. and y=3.91 hours approx.
