Question

Consider the elastic head-on collision between a sledge hammer with 2000 g mass and a golf ball with a 5 g mass. The initial velocity of the sledge hammer is 16 m/s, and the golf ball is initially at rest.

Answer 1

Answer:

v2=6400m/s

Explanation:

Consider the elastic head-on collision between a sledge hammer with 2000 g mass and a golf ball with a 5 g mass. The initial velocity of the sledge hammer is 16 m/s, and the golf ball is initially at rest. the concluding part of this question could be:

this is an elastic collision

we know from the principles of linear momentum that the total momentum before collision must be equal to total linear momentum after collision

momentum is the product of mass and its velocity

m1u1+m2u2=m1v1+m2v2

m1=2000g mass of the sledge hammer

u1=16m/s initial velocity of the sledge hammer

m2=5g mass of the golf ball

u2=0 velocity of the golf ball

v1=0m/s final velocity of the sledge hammer

v2=? final velocity of the golf ball

2000*16+5*0=2000*0+5v2

v2=2000*16/5

v2=400*16

v2=6400 m/s

Answer 2

The final velocity of the golf ball would be:

6400 m/s

Mass and Velocity

Mass of sledge hammer, m₁ = 2000 g

Mass of golf ball, m₂ = 5 g

Initial velocity of hammer, u₁ = 16 m/s

Velocity of ball, u₂ = 0

Final velocity of hammer, v₁ = 0 m/s

We know the relation,

→ m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

By substituting the values,

2000 × 16 + 5 × 0 = 2000 × 0 + 5v₂

                         v₂ = $\frac{2000\times 16}{5}$

                             = $\frac{32000}{16}$

                             = 6,400 m/s

Thus the above response is appropriate.

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