Answer:0.813 m
Explanation:
Given
height at which slide ends is h=1.8 m
Horizontal distance L=2.42 m moved by child from slide base to pool
At slide end Child has only horizontal velocity
horizontal velocity is given by [tex]u=\sqrt{2gH}[/tex]
where H=height of slide
time taken by child to complete 1.8 m height
[tex]t=\sqrt{\frac{2h}{g}}[/tex]
[tex]t=\sqrt{\frac{2\times 1.8}{9.8}}[/tex]
[tex]t=0.606 s[/tex]
Horizontal distance moved in this time
[tex]L=2.42=u\times t[/tex]
[tex]2.42=\sqrt{2gH}\times 0.606[/tex]
[tex]\sqrt{2gH}=3.99[/tex]
[tex]H=0.813 m[/tex]