Question

Let L1 be the line passing through the points Q1(−4, 4, 3) and Q2(0, 10, 1) and let L2 be the line passing through the point P1(3, 20, 0) with direction vector d=[3, −1, −2]T. Determine whether L1 and L2 intersect. If so, find the point of intersection Q.

Answer 1

Answer:

L1 and L2 do not intersect.

Step-by-step explanation:

I am saying that the first line has the initial point Q1 and passes through the vector Q2 - Q1.

Q2 - Q1 = (0,10,1) - (-4,4,3) = (4,6,-2).

So the parametric equations for L1 are:

$x(t) = -4 + 4t$

$y(t) = 4 + 6t$

$z(t) = 3 - 2t$

For L2, we already have a point and the vector, so we can build the parametric equations:

$x(t) = 3 + 3t$

$y(t) = 20 - t$

$z(t) = 0 - 2t$

Now we must find the value of t for which x,y and z are equal. If all are equal at the same time t, these lines intersect at this instant of time.

So

x

$-4 + 4t = 3 + 3t$

$t = 7$

y

$4 + 6t = 20 - t$

$7t = 16$

$t = 2....$

Since the value of t when x are equal is different to when y are equal, these lines do not intersect.