Answer:
Rod will remain horizontal all the time after release.
Explanation:
This is because net torque on the rod about any point in space is zero.
Let assume that distance between the two masses m and 2m is L.
Also m is situated at origin and in positive XY direction.
Then , Center of mass is at L([tex]\frac{mx_{1}+2mx_{2}} }{m +2m}[/tex])
COM =[tex]\frac{2L}{3}[/tex]
So let us calculate net torque about hinged point which COM.
As both torque are equal and opposite then net torque =0.
Thus it got balanced.