An object travels along a horizontal straight path at a constant rate the object travels 1/20 of the length of the path in 3/4 second at that rate how many seconds does it take the object to travel the entire length of the path?
(if you answer please go in depth and explain step by step im slow)​

Respuesta :

Answer:

15 seconds

Step-by-step explanation:

Simply assume that total length to be covered be 'L'.

Now  , [tex]\frac{1}{20}[/tex] of total length L is covered in time [tex]\frac{3}{4}seconds[/tex].

We know distance traveled =speed×time

Let Object's velocity be V

Using this

     [tex]\frac{L}{20}=V×time[/tex]

    [tex]\frac{L}{20}=V*\frac{3}{4}[/tex]

Thus, velocity in terms of total length is

      [tex]V=\frac{L}{15}[/tex]

Now,

 To cover total length L time needed is

[tex]time =\frac{distance}{speed}[/tex]

[tex]time=\frac{L}{\frac{L}{15} }[/tex]

Time taken =15 seconds

Answer:

15 seconds

Step-by-step explanation:

1/20 is a tiny portion of the length that needs to be traveled.  

20/20 is the whole length.

If 1/20 gets traveled in 3/4 of a second

we can multiply 3/4 by 20 to see how long it takes to travel

20(1/20) =

= 1, the whole path.

20(3/4)

= 15 seconds

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