Answer:
The correct answer is option B.
Explanation:
[tex]power(P)=\frac{1}{f}[/tex]
f = focal length
P = -5.5 D (negative power means that lens is concave)
[tex]f=\frac{1}{P}=\frac{1}{-5.5 D}= -0.1818 m[/tex]
1 m = 100 cm
f = -0.1818 m = -0.1818 × 100 cm= -18.18 cm
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex]
[tex]u=\infty [/tex]
[tex]\frac{1}{-18.18 cm}=\frac{1}{\infty }+\frac{1}{v}[/tex]
v = -18.18 cm
v = 1.8 cm - far point
far point = 1.8 cm - v =1.8 cm - (-18.18 cm) = 19.98 cm
But closest answer from the given options is option B.Hence, 20 cm is the correct answer.