Question

In a random sample of 9 cell​ phones, the mean full retail price was ​$546.70 and the standard deviation was ​$195.00. Further research suggests that the population mean is ​$428.87. Does the​ t-value for the original sample fall between minus−t 0.99 and st 0.99?​

Answer 1

Answer:

$t_{stat} = 1.8127$

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = ​$428.87

Sample mean, $\bar{x}$ = ​​$546.70

Sample size, n = 9

Sample standard deviation, s = $195.00

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{546.7 - 428.87}{\frac{195}{\sqrt{9}} } = 1.8127$

Thus, the t-value does not lie in the interval (-0.99,0.99)