Question

I don’t know these so please help me out

Answer 1

Answer:

$BF=45$

Step-by-step explanation:

In the triangle $ABF$ and triangle$ACE$

$BF||CE\\ \Rightarrow \angle ABF=\angle ACE\\ \Rightarrow \angle AFB=\angle AEC\\ \angle A=\angle A$

Hence from $AAA$$\Delta ABF\cong \Delta ACE$

$\frac{BC}{CE}=\frac{AB}{AC}\\\frac{BF}{CE}=\frac{AB}{2AB}\\BF=\frac{1}{2}\times CE\\BF=\frac{1}{2}\times 90\\BF=45$