Question

How many solutions are there to the system of equations? StartLayout enlarged left-brace 1st row 4 x minus 5 y = 5 2nd row negative 0.08 x + 0.10 y = 0.10 EndLayout no solutions one solution two solutions an infinite number of solutions

Answer 1

Answer:

Only one solution  $x=\frac{5}{4},y=0$

Step-by-step explanation:

$4x-5y=5..............(1)\\0.08x+0.10y=0.10...........(2)$

Multiply equation $(2)$ by $50$

$4x-5y=5........(3)$

Now from equation $(1)$$+$ equation$(3)$

$8x=10\\x=\frac{10}{8}\\x=\frac{5}{4}$

Put the value in equation $(1)$

$5-5y=5\\5y=0\\y=0$

hence only one solution exists$\left(\frac{5}{4},0\right)$.

Answer 2

Answer:

im pretty sure the answer is b: one answer only

Step-by-step explanation:

cuz it work