Question

If f (x) = StartFraction x minus 3 Over x EndFraction and g(x) = 5x – 4, what is the domain of (f circle g) (x)? StartSet x vertical line x not-equals 9 EndSet StartSet x vertical line x not-equals one-third EndSet StartSet x vertical line x not-equals four-fifths EndSet StartSet x vertical line x not-equals 3 EndSet

Answer 1

Answer:

Domain$=\{x|x\in R\ and \ x \not=\frac{4}{5}\}$

Step-by-step explanation:

$f(x)=\frac{x-3}{x}\\g(x)=5x-4\\f(g(x))=f(5x-4)\\\\=\frac{5x-4-3}{5x-4} \\\\=\frac{5x-7}{5x-4}$

$f\ o\ g(x)$ is not defined at $x=\frac{4}{5}$

Hence domain will be real line except $x=\frac{4}{5}$

Answer 2

Answer: is {x|x not equal to 4/5

Step-by-step explanation: