Question

express the line passing through the points A(6,-2) and B(-2,8) in y=mx+b form ​

Answer 1

Answer:

Step-by-step explanation:

You first need to find the slope using the slope formula:

$m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }$

For us,

$m=\frac{8-(-2)}{-2-6}=\frac{10}{-8}=-\frac{5}{4}$

Now we have the m value.  Choose one of the points you were given to write the equation.  I am going to use (6, -2) and plug into the slope-intercept form and then solve for y:

$y-(-2)=-\frac{5}{4}(x-6)$ which simplifies a bit to

$y+2=-\frac{5}{4}x+\frac{30}{4}$

Now subtract 2 from both sides, expressing 2 as a fraction with a denominator of 4:

$y=-\frac{5}{4}x+\frac{30}{4}-\frac{8}{4}$ which simplifies finally to

$y=-\frac{5}{4}x+\frac{11}{2}$