Question

a 0.400 kg aluminum teakettle contains 2.00 kg of water at 15.0 degrees celcius. How much heat is required to raise the temperature of the water (and kettle) to 100 degrees celcius

Answer 1

Answer:

Q= 742.22 KJ

Explanation:

Teakettle mass m_{Al}= 0.400 Kg

mass of water m_{water}= 2 Kg

The initial temperature T_i=15°C

Final temperature  T_f=100°C

To find the amount of heat require to raise this temperature

we know that

Q= mcΔT

c= specific heat capacity of material

c for Al= 0.9 KJ/Kg K

c for water = 4.186 KJ/Kg K

m= mass of the material

ΔT= increase in the temperature

Therefore

$Q= m_{Al}c_{Al}\Delta T+m_{water}c_{water}\Delta T$

putting the values we get

$Q=0.4\times0.9(100-15)+2\times4.186(100-15)$

Q= 742.22 KJ