A 3-phase induction motor is being driven at a frequency of 80 Hz, and the motor speed is 1000 rpm. How many poles does the motor probably have and what is the slip? (10 points)

Respuesta :

Answer:

8 poles

Slip= 16.67%

Explanation:

We use the formula for synchronous speed, [tex]N_s=\frac {120 f}{p}[/tex]

Where f is the frequency and p is the number of poles

Since frequency is given as 80 Hz and the motor speed also given as 1000 rpm then making p the subject of the above formula we get

[tex]p=\frac {120 f}{N_s}[/tex]

By substitution

[tex]p=\frac {120 \times 80}{1000}=9.6\approx 8 poles[/tex]

To find the slip, we now use the actual [tex]N_s[/tex] and since we know that [tex]N_s=\frac {120 f}{p}[/tex] and p=8 then

[tex]N_s=\frac {120 \times 80}{8}=1200[/tex]

The motor speed is now [tex]N_r=1000 rpm[/tex]

To find slip, we use the formula

[tex]Slip=\frac {N_s- N_r}{N_s} \times 100[/tex]

Then by substitution

[tex]Slip=\frac {1200-1000}{1200}\times 100=0.166666667\times 100\approx 16.67[/tex]

Therefore, slip=16.67%

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