A certain process has ΔH° > 0, ΔS° < 0, and ΔG° > 0. The values of ΔH° and ΔS° do not depend on the temperature. Which of the following is a correct conclusion about this process? None of the above conclusions is correct. It is non-spontaneous at all T. It is spontaneous at low T. It is spontaneous at all T. It is spontaneous at high T

Respuesta :

Answer: It is non-spontaneous at all T.

Explanation:

According to Gibb's equation:

[tex]\Delta G=\Delta H-T\Delta S[/tex]

[tex]\Delta G[/tex] = Gibbs free energy = +ve

[tex]\Delta H[/tex] = enthalpy change  = +ve

[tex]\Delta S[/tex] = entropy change  = -ve

T = temperature in Kelvin

[tex]\Delta G[/tex]= +ve, reaction is non spontaneous

[tex]\Delta G[/tex]= -ve, reaction is spontaneous

[tex]\Delta G[/tex]= 0, reaction is in equilibrium

Putting in the values:

[tex]\Delta G=(+ve)-T(-ve)[/tex]

[tex]\Delta G=(+ve)(+ve)=+ve[/tex]  

Reaction is non spontaneous at all temperatures.

ACCESS MORE
EDU ACCESS
Universidad de Mexico