Question

Fred is planning to go to dinner each night of this week (Mon-Fri), with each dinner being in one of 10 restaurants. How many possibilities are there if Fred will not go to the same restaurant twice in a raw (or more)? That is, he can go to the same restaurant several times, but not consecutively

Answer 1

Answer:30240

Step-by-step explanation:

Given

Fred is Planning to visit different restaurant Monday to Friday

If Fred will not go to the same restaurant twice in a row or more i.e. he is mot willing to go same restaurant twice then no of Possible ways can be given by

On Monday there are 10 restaurants available

Tuesday 9

Wednesday 8

Thursday 7

Friday 6

Total no of ways are $=10\times 9\times 8\times 7\times 6=30,240$