Respuesta :

If [tex]0<x<\frac\pi2[/tex], then [tex]\cos x>0[/tex].

Recall the double angle identity,

[tex]\cos^2x=\dfrac{1+\cos(2x)}2[/tex]

so we have

[tex]\cos^2\dfrac{3\pi}8=\dfrac{1+\cos\frac{6\pi}8}2=\dfrac{1-\frac1{\sqrt2}}2=\dfrac{2-\sqrt2}4[/tex]

[tex]\implies\cos\dfrac{3\pi}8=\boxed{\dfrac{\sqrt{2-\sqrt2}}2}[/tex]

Answer:

The answer is A.

Step-by-step explanation:

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