Answer:8.69 m/s
Explanation:
Given
mass of Empty train [tex]m=2\times 10^4 kg[/tex]
velocity of car [tex]v=10 m/s[/tex]
mass of Boulder [tex]M=3000 kg[/tex]
Since no External force is acting therefore conserving Momentum
Train and boulder moves with same velocity after collision
[tex]m v=(M+m)v'[/tex]
[tex]2\times 10^4\times 10=(2\times 10^4+3000)v'[/tex]
[tex]v'=\frac{20,000\times 10}{23000}[/tex]
[tex]v'=8.69 m/s[/tex]