Question

A lightning bug flies at a velocity of 0.15 m/s due east toward another lightning bug seen off in the distance. A light easterly breeze blows on the bug at a velocity of 0.15 m/s. What is the resultant velocity of the lightning bug

Answer 1

Answer:0 m/s

Explanation:

Given

velocity of Lightning bug $v_1=0.15 m/s$ (due to east)

Easterly breeze blows on the bug from east has a velocity of $v_2=0.15 m/s$(due to west)

Net velocity is the vector addition of two velocities

taking East as positive and west as negative

$\vec{v_{net}}=\vec{v_1}+\vec{v_2}$

$\vec{v_{net}}=0.15\hat{i}-0.15\hat{i}$

$\vec{v_{net}}=0\hat{i}\ m/s$

Answer 2

The resultant velocity of the lightning bug is mathematically given as

Vr= 0.00m/s

What is the resultant velocity of the lightning bug?

Question Parameters:

A lightning bug flies at a velocity of 0.15 m/s

A light easterly breeze blows on the bug at a velocity of 0.15 m/s.

Generally, the equation for the  resultant velocity   is mathematically given as

Vr=Intial +final velocity

Therefore

Vr=v+u

Vr== 0.15 + (-0.15)

Vr= 0.15 - 0.15

Vr= 0.00m/s

In conclusion,  the resultant velocity

Vr= 0.00m/s

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