Answer:0.918 kg
Explanation:
Given
Object is at a distance of r=3 R from earth surface
where R=radius of Earth
acceleration due to Gravity is given by
[tex]g=\frac{Gm_e}{R^2}[/tex]
at earth surface [tex]g=9.8 m/s^2[/tex]
g at [tex]r=3 R[/tex]
[tex]g'=\frac{Gm_e}{(3R)^2}[/tex]
[tex]g'=\frac{Gm_e}{9R^2}[/tex]
[tex]g'=\frac{g}{9}[/tex]
Weight at r=3R is 1 N
thus Weight at Earth surface will be 9 times at r=3R
weight at Earth surface =9 N
[tex]mass=\frac{9}{9.8}=0.918 kg[/tex]