Respuesta :

frika

Answer:

[tex]-123\dfrac{3}{7}[/tex]

Step-by-step explanation:

Find the infinite geometric sum of -144 +24 - 4 + ...​

The sum of infinite geometric sequence is

[tex]S=\dfrac{b_1}{1-r},[/tex]

where [tex]b_1[/tex] is the first term and [tex]r[/tex] is the common ratio.

In your case,

[tex]b_1=-144,\\ \\b_2=24,\\ \\b_3=-4,\\ \\r=\dfrac{b_2}{b_1}=\dfrac{24}{-144}=-\dfrac{1}{6}\\ \\ \bigskip\ \bigskip\ \bigskip =\dfrac{b_3}{b_2}=\dfrac{-4}{24}=-\dfrac{1}{6}[/tex]

So, the sum is

[tex]S=\dfrac{-144}{1-\left(-\dfrac{1}{6}\right)}=\dfrac{-144}{1+\dfrac{1}{6}}=-\dfrac{144}{\dfrac{7}{6}}=-\dfrac{864}{7}=-123\dfrac{3}{7}[/tex]

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