Explanation:
The given data is as follows.
mass of solute = 64.5 g, mass of solvent = 500 g = 0.5 kg (as 1 kg = 1000 g),
Temperature = [tex]80.10^{o}C[/tex], [tex]K_{b}[/tex] = 2.53 C/m
Also, we know that the relation between change in temperature, van't Hoff factor(i) and [tex]K_{b}[/tex] is as follows.
[tex]\Delta T = iK_{b}m[/tex]
where, m = molality = [tex]\frac{\text{moles of solute}}{\text{kg of solvent}}[/tex]
= [tex]\frac{64.5 g}{129 g/mol} \times \frac{1}{0.5 kg}[/tex]
= 1
It is known that for non-electrolyte solute i = 1.
Hence, putting the given values into the above formula as follows.
[tex]\Delta T = iK_{b}m[/tex]
= [tex]1 \times 2.53 C/m \times 1[/tex]
= 2.53 C
Therefore, calculate the boiling point of the solution as follows.
80.10 C + 2.53 C
= 82.63 C
Thus, we can conclude that the boiling point of the solution is 82.63 C.
