Answer:
there are 1.178*10²⁴ atoms of N in the sample
Explanation:
Assuming that the dinitrogen tetroxide is pure (contains no impurities) then
number of atoms of N in the sample = number of moles in the sample * number of molecules per mole* number of N atoms per molecule
- number of atoms per mole = 6.023*10²³ molecules/mole ( Avogadro's number)
- number of N atoms per molecule = 2 N atoms/molecule
-number of moles in the sample = mass of N2O4 / molecular weight of N2O4
molecular weight of N2O4 = 2* (14 gr/mol) + 4*(16 gr/mole) = 92 gr/mole
thus
number of moles in the sample = 90 gr / 92 gr/mole = 90/92 mole
therefore
number of atoms of N in the sample = 90/92 mole * 6.023*10²³ molecules/mole* 2 N atoms/molecule = 1.178*10²⁴ atoms of N
