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A copper sphere has a radius of 2.50 m under normal room pressure of 1.0 × 105 N/m2. If we increase the pressure on this sphere to 10 times the normal room pressure, what is the change in its volume? The bulk modulus for copper is 1.4 × 1011 Pa

Respuesta :

Answer:

-4.2081 × 10⁻⁴ m³

Explanation:

Volume of the copper sphere = 4/3 π r³ where r is the radius of the sphere which = 2.50 m

Volume of copper Vo = 4/3 × 3.142 × 2.5³ = 65.46 m³

Bulk modulus = - VoΔp / ΔV where Vo is the initial volume of the sphere, Δp is the change in pressure in N/m² and ΔV is the change in volume

make ΔV subject of the formula

ΔV = -VoΔp / B = (-65.46 × ( 10 - 1) ×10⁵) / (1.4 × 10¹¹)

ΔV = -589.14 × 10⁵ / ( 1.4 × 10 ¹¹) = - 420.81 × 10 ⁻⁶ m³ = -4.2081 × 10⁻⁴ m³

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