Answer:
c)
Step-by-step explanation:
To solve this, remember some properties of trigonometric functions.
Let [tex]y=\tan^{-1} (x)[/tex]. Then, by definition of inverse function, [tex]\tan(y)=x[/tex]. Multiply by -1 to both sides of this equation to get [tex]-\tan(y)=-x[/tex].
Note that [tex]-\tan(y)=\frac{-\sin(y)}{\cos(y)}=\frac{\sin(-y)}{\cos(y)}=\frac{\sin(-y)}{\cos(-y)}=\tan(-y)[/tex] because sine is an odd function and cosine is an even function. Then [tex]\tan(-y)=-x[/tex]. Take the inverse tangent in both sides to get [tex]-y=\tan^{-1} (-x)[/tex].
Using the previous equations, we obtain:
[tex]\tan^{-1} (x)+\tan^{-1} (-x)=y+(-y)=0[/tex]