Respuesta :
Answer:
We conclude that hippocampal volumes in the alcoholic adolescents were less than the normal volume of 9.02 cm cubed.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 9.02
Sample mean, [tex]\bar{x}[/tex] = 8.16
Sample size, n = 23
Alpha, α = 0.01
Sample standard deviation, s = 0.7
First, we design the null and the alternate hypothesis
[tex]H_{0}: \mu = 9.02\text{ cm cubed}\\H_A: \mu < 9.02\text{ cm cubed}[/tex]
We use one-tailed t test to perform this hypothesis.
Formula:
[tex]t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }[/tex]
Putting all the values, we have
[tex]t_{stat} = \displaystyle\frac{8.16 - 9.02}{\frac{0.7}{\sqrt{23}} } = -5.892[/tex]
Now,
[tex]t_{critical} \text{ at 0.01 level of significance, 22 degree of freedom } = -2.508[/tex]
Since,
[tex]t_{stat} < t_{critical}[/tex]
We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.
We conclude that hippocampal volumes in the alcoholic adolescents were less than the normal volume of 9.02 cm cubed.