If a rod is moving at a velocity equal to 1/2 the speed of light parallel to its length, what will a stationary observer observe about its length?

Respuesta :

Answer:

The length of the rod will decrease.

Explanation:

According to Einstein's relativity theory we know that

[tex]L=L_0\times\sqrt{1-(v/c)^2}[/tex]

where Lo= initial length of the rod

v= velocity of moving rod= c/2

c= velocity of light

put v= c/2 we get

L= 0.866 L₀

Therefore, The length of the rod will decrease.

Answer:

The length of the  is 0.866 L₀.

Explanation:

Given that,

Velocity of rod = half the speed of light

We need to calculate the length

Using formula of length

[tex]L=L_{0}\sqrt{1-(\dfrac{v}{c})^2}[/tex]

Where, L= length

v = velocity of rod

c = speed of light

L₀ = observer length

Put the value into the formula

[tex]L=L_{0}\sqrt{1-(\dfrac{(0.5c)^2}{c^2})}[/tex]

[tex]L=L_{0}\sqrt{1-(0.5)^2}[/tex]

[tex]L=0.866L_{0}[/tex]

The length of the rod will decreases

Hence, The length of the rod is 0.866 L₀.

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