Question

Each of the 25 balls in a certain box is either red, blue, or white, and has a number from 1 to 10 painted on it. If one ball is to be selected at random from the box, what is the probability that the ball selected will either be white or have an even number painted on it?

Answer 1

Answer:

Pr(W or E) = 2Pr(E) + 0.2

Step-by-step explanation:

Let R represent Red balls

Let W represent White balls

Let B represent blue balls

Probability of picking white balls = Pr(W)

Probability of picking an even ball = Pr(E)

The probability that the ball will both be white and have an even number painted on it is 0

Pr(W or E) = Pr(W) + Pr(E) - 0

The probability that the ball will be white minus the probability that the ball will have an even number painted on it 0.2

Pr(W) - Pr(E) = 0.2

Pr(W) = Pr(E) + 0.2

Pr(W or E) = Pr(E) + 0.2 + Pr(E)

Pr(W or E) = 2Pr(E) + 0.2

Multiple answers are possible