Respuesta :
Answer:
Step-by-step explanation:
Given
height of two Poles are 60 and 80 ft
Distance between them is 100 ft
Let x be the distance of Pole of ht 80 ft from Point of stretch
thus length of rope is given by
[tex]L=L_1+L_2[/tex]
[tex]L_1=\sqrt{80^2+x^2}[/tex]
[tex]L_2=\sqrt{60^2+(100-x)^2}[/tex]
[tex]L=\sqrt{80^2+x^2}+\sqrt{60^2+(100-x)^2}[/tex]
differentiate w.r.t x we get
[tex]\frac{\mathrm{d} L}{\mathrm{d} x}=\frac{2x}{2\sqrt{80^2+x^2}}-\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}[/tex]
Put [tex]\frac{\mathrm{d} L}{\mathrm{d} x}=0[/tex] to get minimum value
[tex]\frac{2x}{2\sqrt{80^2+x^2}}=\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}[/tex]
squaring
[tex]x^2\left ( (100-x)^2+60^2\right )=(100-x)^2(80^2+x^2)[/tex]
Rearranging
[tex]28x^2-1800x+640000=0[/tex]
[tex]x=\frac{400}{7}[/tex]
thus [tex]L_1=98.312 ft[/tex]
[tex]L_2=73.73 ft[/tex]
[tex]L=172.04 ft[/tex]

By using right triangles such that the cable is the hypotenuse of the triangles, we will see that the minimum length is:
L = 172.55 ft
How to get the minimum length of cable?
The minimum length is the length that we get when the cable forms the hypotenuses of two right triangles, such that the cathetus are the height of the poles and half of the distance between their bases.
So, for one of the triangles the cathetus measure 80ft and 50 ft (half of the distance between the two poles), then if we use the Pythagorean theorem, the length of the hypotenuse is:
H^2 = 80ft^2 + 50ft^2
H = √(80ft^2 + 50ft^2 ) = 94.45 ft
For the other pole, the cathetus measures 60ft and 50ft, then the hypotenuse in this case is:
H^2 = 60ft^2 + 50ft^2
H = √(60ft^2 + 50ft^2 ) = 78.10 ft
The total length of the cable will be:
L = 94.45 ft + 78.10 ft = 172.55 ft
If you want to learn more about right triangles, you can read:
https://brainly.com/question/2217700