Help help help!!!!!!!!!!

Answer:
Step-by-step explanation:
[tex]4(z+1)=2(z-1)+18\qquad\text{use the distributive property}\\\\(4)(z)+(4)(1)=(2)(z)+(2)(-1)+18\\\\4z+4=2z-2+18\qquad\text{subtract 4 and}\ 2z\ \text{from both sides}\\\\4z-2z+4-4=2z-2z-2+18-4\qquad\text{combine like terms}\\\\2z=12\qquad\text{divide both sides by 2}\\\\z=6[/tex]