Answer:
The partial pressure of nitrogen is 597.5 torr
Explanation:
Step 1: Data given
Mol fraction of N = 0.781
Mol fraction of O = 0.209
Mol fraction Ar = 0.010
Atmospheric pressure = 765.0 torr
The partial pressure is given by Pi = Xi * Pt
⇒ χ i = the mole fraction of gas i in the mixture
⇒ P total = the total pressure of the mixture
Step 2: Calculate the partial pressure of nitrogen
P(N) = mol fraction of N * atmospheric pressure
P(N) = 0.781 * 765.0 torr = 597.5 torr
The partial pressure of nitrogen is 597.5 torr
