Respuesta :
Answer:
[tex]a_1=-10[/tex]
[tex]d=3[/tex]
Step-by-step explanation:
we know that
In an Arithmetic Sequence the difference between one term and the next is a constant, and this constant is called the common difference (d)
In this problem we have the ordered pairs
[tex](1,-10),(2,-7),(3,-4),(4,-1),(5,2),(6,5)[/tex]
Let
[tex]a_1=-10\\a_2=-7\\a_3=-4\\a_4=-1\\a_5=2\\a_6=5[/tex]
Find the difference between one term and the next
[tex]a_2-a_1=-7-(-10)=3[/tex]
[tex]a_3-a_2=-4-(-7)=3[/tex]
[tex]a_4-a_3=-1-(-4)=3[/tex]
[tex]a_5-a_4=2-(-1)=3[/tex]
[tex]a_6-a_5=5-2=3[/tex]
The difference between one term and the next is a constant
This constant is the common difference
so
The sequence graphed is an Arithmetic Sequence
therefore
The first term is [tex]a_1=-10[/tex]
The common difference is equal to [tex]d=3[/tex]