Answer:
a.
The higher quantum number is n+1 = 12 +1 =13
b.
The higher quantum number is n = 12
c.
[tex]E_{n+1} -E_{n}=E_{6}=6^{2}E_{1}=(2n+1)E_{1} \\n=17.5[/tex]
this is not integer so impossible to find pair of adjacent level
Explanation:
Let the quantum number pair will be n and n+1
equation of energy of particle in one dimensional box is = [tex]\frac{n^{2}h^{2}}{8mL^{2}}[/tex]
[tex]E_{n+1} -E_{n}=\frac{(n+1)^{2}h^{2}}{8mL^{2}}-\frac{n^{2}h^{2}}{8mL^{2}}[/tex]
[tex]E_{n+1} -E_{n}=\frac{(2n+1)^{}h^{2}}{8mL^{2} }[/tex]
[tex]E_{n+1} -E_{n}=(2n+1)E_{1}[/tex]
Which leads to
2n+ 1 =25
n= 12
a.
The higher quantum number is n+1 = 12 +1 =13
b.
The higher quantum number is n = 12
c.
[tex]E_{n+1} -E_{n}=E_{6}=6^{2}E_{1}=(2n+1)E_{1} \\n=17.5[/tex]
this is not integer so impossible to find pair of adjacent level