Question

Two long, parallel wires are separated by a distance of 3.40 cm . The force per unit length that each wire exerts on the other is 3.60×10−5 N/m , and the wires repel each other. The current in one wire is 0.640 A

Answer 1

Answer:

Current in second wire, $I_2=9.562\ A$

Explanation:

It is given that,

Separation between two parallel wire, $d=3.4\ cm=3.4\times 10^{-2}\ m$

Force per unit length each wire exerts on the other is, $\dfrac{F}{l}=3.6\times 10^{-5}\ N/m$

Current in wire 1, $I_1=0.64\ A$

Let $I_2$ is the current in other wire. The force acting per unit length is given by :

$\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi d}$

$I_2=\dfrac{2\pi d}{\mu_oI_1}\times \dfrac{F}{l}$

$I_2=\dfrac{2\pi\times 3.4\times 10^{-2}}{4\pi \times 10^{-7}\times 0.64}\times 3.6\times 10^{-5}$

$I_2=9.562\ A$

So, the current in the second wire is 9.562 A. Hence, this is the required solution.