Question

You have 3 balls at the same height. 1 is throws at 45 degrees, 1 is thrown horizontally, 1 is thrown, 1 is thrown at -45 degrees. Rank them by the magnitude of their vertical component of velocity right before they hit the ground.

Answer 1

Answer:

So vertical velocity of ball first and third are same and of ball third less than first and second

$v_{y1}=v_{y3}> v_{y2}$

Explanation:

Let the actual velocity of all balls are v

We have given three balls are thrown are different angle

First is thrown at an angle of 45 degree

So vertical velocity $v_y=vsin\Theta =vsin45^{\circ}=0.707v$

Second ball is thrown horizontally

So vertical velocity $v_y=vsin\Theta =vsin0^{\circ}=0$

Now last ball is thrown is at an angle of -45 degree 'So vertical velocity

$v_y=vsin\Theta =vsin(-45)^{\circ}=-707v$

Which magnitude is equal to 0.707 v

So vertical velocity of ball first and third are same and of ball third less than first and second

$v_{y1}=v_{y3}> v_{y2}$