Answer:
A=3 and B=6
Step-by-step explanation:
Increasing and Decreasing Intervals of Functions
Given f(x) as a real function and f'(x) its first derivative.
If f'(a)>0 the function is increasing in x=a
If f'(a)<0 the function is decreasing in x=a
If f'(a)=0 the function has a critical point in x=a
As we can see, the critical points may define open intervals where the function has different behaviors.
We have
[tex]f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9[/tex]
Computing the first derivative:
[tex]f' ( x ) = - 6 x^3 + 54 x - 108[/tex]
We find the critical points equating f'(x) to zero
[tex]- 6 x^3 + 54 x - 108=0[/tex]
Simplifying by -6
[tex]x^2 -9 x +18=0[/tex]
We get the critical points
[tex]x=3,\ x=6[/tex]
They define the following intervals
[tex](-\infty,3),\ (3,6),\ (6,+\infty)[/tex]
Thus A=3 and B=6