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A sled of mass 3 kg slides along the ice. It has an initial speed of 5 m/s but stops because of friction. How much work is done by friction?
A. 0 J
B. 75 J
C. -75 J
D. -37.5 J

Respuesta :

Answer:

W = -37.5 J

Explanation:

Work And Energy

The work-energy theorem indicates that the work done by forces acting on an object equals the change in the kinetic energy experienced by the object. If the kinetic energy is lost during the experience, the work is negative.

[tex]W=\Delta K[/tex]

[tex]\displaystyle K_1=\frac{mv_1^2}{2}[/tex]

[tex]\displaystyle K_2=\frac{mv_2^2}{2}[/tex]

[tex]\displaystyle \Delta K=\frac{mv_2^2}{2}-\frac{mv_1^2}{2}[/tex]

We have: [tex]v_1=5\ m/s, v_2=0, m= 3\ kg[/tex]

[tex]\displaystyle \Delta K=\frac{(3)0^2}{2}-\frac{(3)5^2}{2}[/tex]

[tex]\displaystyle \Delta K=-\frac{75}{2}=-37.5\ J[/tex]

The work done by the friction force is

[tex]W=-37.5\ J[/tex]

Answer:

D. -37.5 J

Explanation:

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