Question

A car travelling at 20.0 m/s starts to accelerate at 1.00 m/s2. After 5.00 s,
a) how fast is the car travelling and
b) the distance that it has travelled in that time. BTW,
c) how fast is 20.0 m/s in mph and
d) how far has the car travelled in ft

Answer 1

Answer:

Explanation:

Given

Initial speed of car $u=20 m/s$

acceleration $a=1 m/s^2$

$t=5 s$

acceleration is change in velocity over a period of time

$a=\frac{v-u}{t}$

$1=\frac{v-20}{5}$

$v=25 m/s$

(b)distance traveled s

$v^2-u^2=2 as$

$25^2-20^2=2\times 1\times s$

$s=\frac{225}{2}$

$s=112.5 m$

(c)20 m/s is 44.73 mph

as 1 m/s is 2.23 mph

(d)112.5 m in ft

369.1 ft

as 1 m is 3.28 ft