Question

A 5.0 kg box accelerates to the left while on the floor. It accelerates with a net force of 100 N (in spite of the 200 N of friction it encounters). What is the name of the force that accelerates the box?

Answer 1

Answer:

Net force.

Explanation:

Given that

m = 5 kg

Net force ,F(net) = 100 N

Friction force ,Fr= 200 N

From the second law of Newton's

F(net) = m a

m= Mass  

a= acceleration

F(net) =  Net force act on the body

Therefore we can say that, the name of the force that will accelerate the box will be a Net force.

That is why the answer will be Net force.

Answer 2

Answer:

Explanation:

Given

mass of box $m=5 kg$

Net force $F_{net}=100 N$

frictional Force $f_r=200 N$

using FBD

$F-f_r=F_{net}$

$F_{net}=ma_{net}$

So the force acting on block which accelerates it is Net force